# chap10 - 107 Chapter 10 Mechanism Trains 10.1 Find the...

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Unformatted text preview: 107 Chapter 10 Mechanism Trains 10.1 Find the speed and direction of gear 8 in the figure. What is the kinematic coefficient of the train? 5 7 2 4 8/ 2 3 5 6 8 18 15 33 16 5 44 33 36 48 88 N N N N N N N N θ ′ = = = + Ans. ( 29 ( 29 8 8/2 2 5 88 1 200 rev/min ccw 68.18 rev/min ccw ϖ θ ϖ ′ = = + = Ans. 10.2 Part ( a ) of the figure gives the pitch diameters of a set of spur gears forming a train. Compute the kinematic coefficient of the train. Determine the speed and direction of rotation of gears 5 and 7. 2 4 5/ 2 3 5 7 in 9 in 7 15 in 30 in 50 R R R R θ ′ = = = + 5 6 7/ 2 5/ 2 6 7 7 30 in 9 in 21 50 9 in 16 in 80 R R R R θ θ ′ ′ = = = + Ans. ( 29 ( 29 5 5/ 2 2 7 50 120 rev/min cw 16.80 rev/min cw ϖ θ ϖ ′ = = + = Ans. ( 29 ( 29 7 7/ 2 2 21 80 120 rev/min cw 31.50 rev/min cw ϖ θ ϖ ′ = = + = Ans. 10.3 Part ( b ) of the figure shows a gear train consisting of bevel gears, spur gears, and a worm and worm gear. The bevel pinion is mounted on a shaft which is driven by a V- belt on pulleys. If pulley 2 rotates at 1200 rev/min in the direction shown, find the speed and direction of rotation of gear 9. 6 8 2 4 9/ 2 3 5 7 9 6 in 18 20 3 3 10 in 38 48 36 304 N N R N R N N N θ ′ = = = ( 29 ( 29 9 9/ 2 2 3 304 1 200 rev/min 11.84 rev/min cw ϖ θ ϖ ′ = = = Ans. 108 10.4 Use the truck transmission of Fig. 10.2 and an input speed of 3000 rev/min to find the drive shaft speed for each forward gear and for reverse gear. First gear: 6 2 9/ 2 3 9 17 17 289 43 43 1 849 N N N N θ ′ = = = + ( 29 ( 29 9 9/ 2 2 289 1 849 3 000 rev/min 468.9 rev/min ϖ θ ϖ ′ = = = Ans. Second gear: 5 2 8/ 2 3 8 17 27 153 43 33 473 N N N N θ ′ = = = + ( 29 ( 29 8 8/2 2 153 473 3 000 rev/min 970.4 rev/min ϖ θ ϖ ′ = = = Third gear: 2 4 7/ 2 3 7 17 36 51 43 24 86 N N N N θ ′ = = = + ( 29 ( 29 7 7/ 2 2 51 86 3 000 rev/min 1 779.1 rev/min ϖ θ ϖ ′ = = = Fourth gear: 2/ 2 1.0 θ ′ = ( 29 ( 29 2 2/ 2 2 1.0 3 000 rev/min 3 000 rev/min ϖ θ ϖ ′ = = = Reverse gear: 6 2 11 9/ 2 3 10 9 17 17 22 3 179 4318 43 16 641 N N N N N N θ ′ = - = - = - ( 29 ( 29 9 9/ 2 2 3 179 16 641 3 000 rev/min 573.1 rev/min ϖ θ ϖ ′ = = - = - 10.5 The figure illustrates the gears in a speed-change gearbox used in machine tool applications. By sliding the cluster gears on shafts B and C , nine speed changes can be obtained. The problem of the machine tool designer is to select tooth numbers for the various gears so as to produce a reasonable distribution of speeds for the output shaft. The smallest and largest gears are gears 2 and 9, respectively. Using 20 teeth and 45 teeth for these gears, determine a set of suitable tooth numbers for the remaining gears. What are the corresponding speeds of the output shaft? Notice that the problem has many solutions....
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chap10 - 107 Chapter 10 Mechanism Trains 10.1 Find the...

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