CH-20 COULOMB'S LAW-WEB - Chapter 20 Coulombs Law...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 20 Coulomb’s Law (Additional Questions) 1- Two identical conducting small spheres are placed with their centers 0.300 m apart. One is given a charge of 12.0 nC and the other is given a charge of -18.0 nC. (a) Find the electric force exerted on one sphere by the other. (b) The spheres are connected by a conducting wire. Find the electric force between the two after equilibrium has occured. Solution: (a) The force is one of attraction . The distance r in Coulomb’s law is the distance between centers. The magnitude of the force is (b) The net charge of −6.00×10 −9 C will be equally split between the two spheres, or −3.00×10 −9 C on each. The force is one of repulsion , and its magnitude is 2- In figure, three charge particles lie on a straight line and are separated by distances d . Charges 1 q and 2 q are held fixed. Charge 3 q is free to move but happens to be in equilibrium (no net electrostatic force acts on it). Find 1 q in terms of 2 q . Solution: With rightwards positive, the net force on 3 q is ( 29 2 3 2 2 3 1 2 d q q k d q q k + We note that each term exhibits the proper sign (positive for rightward, negative for leftward) for all possible signs of the charges. For example, the first term (the force exerted on 3 q by 1 q ) is negative if they are unlike charges, indicating that 3 q is being pulled toward 1 q , and it is
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 4

CH-20 COULOMB'S LAW-WEB - Chapter 20 Coulombs Law...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online