SOL QUIZ # 6

SOL QUIZ # 6 - =0.5 m 0.5 m 0.5 28 0.5 m 35 g/mol m...

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Name: MSE 230- REC 5&6 QUIZ # 6 1. Polymers An alternating copolymer has the following molecular weight distribution. Molecular weight range (g/mol) Number fraction (x i ) 0-10000 0.1 10000-20000 0.55 20000-30000 0.35 Calculate the number average molecular weight? 0.1 5000 + 0.55 15000 + 0.35 25000 = 17500 g/mol n M = × × × One of the polymers used for this copolymer is Polyethylene. Knowing that the degree of polymerization of the copolymer is 500, which of the following polymers is the other polymer? Polyethylene - m (repeating unit) = 28 g/mol Polypropylene - m (repeating unit) = 42 g/mol Polyvinyl chloride - m (repeating unit) = 62 g/mol PE UNKNOWN UNKNOWN UNKNOWN 17500 500 Alternating copolymer: Polyethylene (PE)/Unknown
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Unformatted text preview: =0.5 m +0.5 m 0.5 28 0.5 m 35 g/mol m Unknown= 35 g/mol 42 g/mol Polypropylene n M m DP m = = = × × = × + × = ⇒ = ⇒ 2. Composite A carbon-fiber reinforced nylon 6,6 composite is loaded along the longitudinal direction (fiber direction). The fibers are continuous and aligned. Their volume fraction is 0.4. E Carbon = 260 GPa E Nylon 6,6 = 2.8 GPa This type of loading is _ Isostrain ______. (Isostrain or Isotress). The Elastic modulus E of the composite is __ 105.68_ _GPa. 0.6 0.4 105.68 C nylon Carbon E E E GPa = + = The fraction of the load carried by the fibers is _ 0.9841 _. 0.4 260 0.9841 105.68 f f f f total f m f f m m F F E V F F F E V E V × = = = = + +...
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This note was uploaded on 04/03/2012 for the course MSE 230 taught by Professor Trice during the Spring '08 term at Purdue.

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