2009Chp26Soln - 26.16. Model: Charges A, B, and C are point...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 26.16. Model: Charges A, B, and C are point charges. Visualize: Please refer to Figure EX26.16. Charge A experiences an electric force B on A F r due to charge B and an electric force C on A F r due to charge C. The force B on A F r is directed to the right and the force C on A F r is directed to the left. Solve: Coulombs law yields: ( 29 ( 29 ( 29 ( 29 9 2 2 9 9 5 B on A 2 2 9.0 10 N m /C 1.0 10 C 1.0 10 C 9.0 10 N 1.0 10 m F---- = = ( 29 ( 29 ( 29 ( 29 9 2 2 9 9 5 C on A 2 2 9.0 10 N m /C 1.0 10 C 4.0 10 C 9.0 10 N 2.0 10 m F---- = = The net force on A is ( 29 ( 29 ( 29 5 5 on A B on A C on A 9.0 10 N 9.0 10 N 0 N F F F i i-- = + = + - = r r r 26.18. Model: Objects A and B are point charges. Visualize: Because there are only two charges A and B, the force on charge A is due to charge B only, and the force on B is due to charge A only. Solve: Coulombs law gives the magnitude of the forces between the charge. Thus, F A on B = F B on A = 9.0 10 9 N m 2 /C 2 ( 29 20.0 10- 9 C ( 29 10.0 10- 9 C ( 29 2.0 10- 2 m ( 29 2 = 4.5 10- 3 N Because the charge on object A is positive and on object B is negative, F B on A is upward and F A on B is downward. Thus, r F B on A = + 4.5 10- 3 j N r F A on B = - 4.5 10- 3 j N 26.26. Model: A field is the agent that exerts an electric force on a charge. Visualize: Solve: (a) To balance the gravitational force on a proton ( 29 ( 29 net on p p G y F F F =- = r r N. This means ( 29 ( 29 ( 29 27 7 on p 19 p 1.67 10 kg 9.8 N/kg 1.02 10 N/C 1.60 10 C G mg F F q E mg E q--- = = = = = Because F on p must be upward and the proton charge is positive, the electric field at the location of the proton must also be pointing upward. Thus ( 29 7 1.02 10 N/C, downward . E- = r (b) In the case of the electron, ( 29 ( 29 31 11 19 9.11 10 kg 9.8 N/kg 5.58 10 N/C 1.60 10 C mg E q--- = = = Because F on e must be upward and the electron has a negative charge, the electric field at the location of the electron must be pointing downward. Thus electron must be pointing downward....
View Full Document

This note was uploaded on 04/03/2012 for the course PHYSICS AN 101 taught by Professor N.a during the Spring '12 term at Clark College.

Page1 / 7

2009Chp26Soln - 26.16. Model: Charges A, B, and C are point...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online