Ch3-HW1 –florin –(56950)1This print-out should have 23 questions. Multiple-choice questions may continue on the next column or page –find all choices before answering.Problem @22: calculate the difference in the magnitudes of the fields, not the forces.001 (part 1 of 4) 10.0 pointsEach part of this problem will state an ex-ample of objects interacting via some force. Choose the fundamental interaction that is responsible in each case.A neutron outside a nucleus decays into a proton, electron, and antineutrino.1. Strong 2. Gravitational 3. Weak correct 4. Electromagnetic Explanation:Notice the presence of an antineutrino in this decay. Neutrinos (and their antiparticle partners) only interact via the weak force, so this must be a weak interaction.002 (part 2 of 4) 10.0 pointsProtons and neutrons attract each other ina nucleus. 1. Gravitational 2. Strong correct 3. Weak 4. Electromagnetic Explanation:The force that holds the nucleus together must be strong enough to overcome the repul-sion between protons due to the electromag-netic force. This is a strong interaction.003 (part 3 of 4) 10.0 pointsThe Earth pulls on the Moon.1. Gravitational correct 2. Weak 3. Electromagnetic 4. Strong Explanation:This is a gravitational interaction, in which massive bodies attract each other.004 (part 4 of 4) 10.0 pointsProtons in a nucleus repel each other.1. Gravitational 2. Weak 3. Electromagnetic correct 4. Strong Explanation:This is an example of an electromagnetic in-teraction, in which particles with like charges repel.005 (part 1 of 2) 10.0 pointsThemassofthe Sunis 2 × 1030kg,andthemassofMercuryis3.3 × 1023kg.Thedistancefrom theSunto Mercury is4.8 × 1010m.First, calculate the magnitude of the gravi-tational force exerted by the Sun on Mercury.Use G = 6.67 × 10−11m3. kg · s2Correct answer: 1.91068 × 1022N.Explanation:The magnitude of the gravitational force between two objects is given byF~gr=₃−Gm1m2₃=Gm1m2.₃₃22₃₃₃₃rr₃₃₃₃₃₃We just need to plug in the given constants to find the answer:₃F~gr₃= Gm12m2₃₃r
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