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# 11_new - Homework#10 holcombe(51160 This print-out should...

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Homework #10 holcombe (51160) 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Balance the reaction Fe(NO 3 ) 2 + HNO 3 Fe(NO 3 ) 3 + NO + H 2 O . What is the coe cient of H 2 O in the bal- anced equation? Correct answer: 2. Explanation: The balanced equation is 3 Fe(NO 3 ) 2 + 4 HNO 3 3 Fe(NO 3 ) 3 + NO + 2 H 2 O . 3 10.0 points Balance the reaction NaCrO 2 + NaOH + H 2 O 2 Na 2 CrO 4 + H 2 O . What is the coe cient of NaOH in the bal- anced equation? Correct answer: 2. Explanation: The balanced equation is 2 NaCrO 2 + 2 NaOH + 3 H 2 O 2 2 Na 2 CrO 4 + 4 H 2 O . 003 10.0 points For an electrochemical reduction process, electrons are 1. added to solution species at the surface of the anode. 2. added to solution species at the surface of the cathode. correct 3. taken from solution species at the surface of the cathode. Explanation: 004 10.0 points Consider the following reaction taking place in a voltaic cell: Cu(s) + 2Ag + (aq) Cu 2+ (aq) + 2Ag(s) 1. Cu is reduced at the anode and Ag + is oxidized at the cathode. 2. Cu is oxidized at the anode and Ag + is reduced at the cathode. correct 3. Cu is oxidized at the cathode and Ag + is reduced at the anode. 4. Cu is reduced at the cathode and Ag + is oxidized at the anode. Explanation: Oxidation is loss of electrons and occurs at the anode which is what happens to the copper metal (Cu). Reduction is gain of elec- trons and occurs at the cathode which is what happens to the silver ion (Ag + ) 005 10.0 points Consider a voltaic cell based on the redox reaction Zn + Cl 2 ZnCl 2 . The half cell reaction occuring at the anode is 1. None of these 2. Zn 2+ + 2 Cl ZnCl 2 3. Zn Zn 2+ + 2 e correct 4. Cl 2 + 2 e 2 Cl Explanation: Oxidation (loss or production of e ) always occurs at the anode.

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11_new - Homework#10 holcombe(51160 This print-out should...

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