DiscGQ07
–
gilbert
–
(55035)
1
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printout
should
have
4
questions.
z
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questions
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find
all
choices
before answering.
001
10.0 points
Which
one
of
the
following
equations
has
graph
x
But this circle has radius 2 because the cylin
der has radius 2, and so its equation is
x
2
+ (z
−
2)
2
=
4
as
a
circle
in
the
xzplane.
Consequently,
after expansion we see that the cylinder is the
graph of the equation
when the circular cylinder has radius 2.
x
2
+ z
2
−
4z
=
0
.
1. x
2
+ z
2
−
4z
=
0 correct
2. x
2
+ z
2
−
2z
=
0
3. z
2
+ x
2
+ 2x
=
0
4. z
2
+ x
2
+ 4x
=
0
5. y
2
+ z
2
+ 2z
=
0
6. y
2
+ z
2
+ 4z
=
0
Explanation:
The graph is a circular cylinder whose axis
of symmetry is parallel to the yaxis, so it will
be the graph of an equation containing no y
term. This already eliminates the equations
keywords:
quadric
surface,
graph
of
equation, cylinder, Surfaces, SurfacesExam,
3D graph, circular cylinder, trace
002
10.0 points
Determine f
Y
when
f (x, y)
=
sin(x
−
y)
−
y cos(x
−
y) .
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 Spring '07
 Sadler
 Derivative, Sin, Cos, xy, Circular Cylinder

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