26_new - DiscGQ07 gilbert (55035) 1 This print-out should...

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DiscGQ07 – gilbert – (55035) 1 This print-out should have 4 questions. z Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Which one of the following equations has graph x But this circle has radius 2 because the cylin- der has radius 2, and so its equation is x 2 + (z − 2) 2 = 4 as a circle in the xz-plane. Consequently, after expansion we see that the cylinder is the graph of the equation when the circular cylinder has radius 2. x 2 + z 2 − 4z = 0 . 1. x 2 + z 2 − 4z = 0 correct 2. x 2 + z 2 − 2z = 0 3. z 2 + x 2 + 2x = 0 4. z 2 + x 2 + 4x = 0 5. y 2 + z 2 + 2z = 0 6. y 2 + z 2 + 4z = 0 Explanation: The graph is a circular cylinder whose axis of symmetry is parallel to the y-axis, so it will be the graph of an equation containing no y- term. This already eliminates the equations keywords: quadric surface, graph of equation, cylinder, Surfaces, SurfacesExam, 3D graph, circular cylinder, trace 002 10.0 points
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This note was uploaded on 04/04/2012 for the course M 408d taught by Professor Sadler during the Spring '07 term at University of Texas at Austin.

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26_new - DiscGQ07 gilbert (55035) 1 This print-out should...

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