{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# 26_new - DiscGQ07 gilbert(55035 1 This print-out should...

This preview shows pages 1–2. Sign up to view the full content.

DiscGQ07 gilbert (55035) 1 This print-out should have 4 questions. z Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Which one of the following equations has graph x But this circle has radius 2 because the cylin- der has radius 2, and so its equation is x 2 + (z 2) 2 = 4 as a circle in the xz-plane. Consequently, after expansion we see that the cylinder is the graph of the equation when the circular cylinder has radius 2. x 2 + z 2 4z = 0 . 1. x 2 + z 2 4z = 0 correct 2. x 2 + z 2 2z = 0 3. z 2 + x 2 + 2x = 0 4. z 2 + x 2 + 4x = 0 5. y 2 + z 2 + 2z = 0 6. y 2 + z 2 + 4z = 0 Explanation: The graph is a circular cylinder whose axis of symmetry is parallel to the y-axis, so it will be the graph of an equation containing no y- term. This already eliminates the equations keywords: quadric surface, graph of equation, cylinder, Surfaces, SurfacesExam, 3D graph, circular cylinder, trace 002 10.0 points Determine f Y when f (x, y) = sin(x y) y cos(x y) .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 3

26_new - DiscGQ07 gilbert(55035 1 This print-out should...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online