Exercise 2.1
Exercise 2.1, Solution 1:
a.
The 2
nd
term is 7
x
y
, and the 3
rd
term is 4
y
b.
The 3
rd
term is
y
, and the 4
th
term is 3
c.
The 1
st
term is 9
x
y
, and the 3
rd
term is 6
y
Exercise 2.1, Solution 3:
a.
The coefficient of the first term 5
x
2
is 5, the coefficient of the second term 3
x
y
is 3, and the
constant term is 5.
b.
The coefficient of the first term, 2
y
2
is 2, the coefficient of the second term, 3
x
, is 3 and the
constant term is 1.
c.
The coefficient of the first term, 2
x
y
2
is 2, the coefficient of the second term, 2
x
2
y
, is 2 and the
constant term is 7.
d.
The coefficient of the first term, 8
y
2
, is 8, and the constant term is 4.
Exercise 2.1, Solution 5:
a.
13
x
2
+ 8
x
– 2
x
2
+ 9
x
Grouping like terms together, we obtain
= 13
x
2
– 2
x
2
+ 8
x
+ 9
x
Adding and subtracting like terms, we obtain
= 11
x
2
+ 17
x
Therefore, the simplified given expression is 11
x
2
+ 17
x.
b.
– 18
y
– 5
y
2
+ 19
y
– 2
y
2
Grouping like terms together, we obtain
= – 18
y
+ 19
y
– 2
y
2
– 5
y
2
Adding and subtracting like terms, we obtain
=
y
7
y
2
Therefore, the simplified given expression is
y
7
y
2
.
c.
6
x
– 3
x
+ 2
y
2
+
y
2
Adding and subtracting like terms, we obtain
= 3
x
+ 3
y
2
Therefore, the simplified given expression is 3
x
+ 3
y
2
.
Exercise 2.1, Solution 7:
a.
Adding and subtracting like terms together, we obtain