P = B
R
= 50
0.10 = $5 (this is the amount of discount).
Therefore, he paid = 50
–
5 = $45.00 for the pair of shoes.
Exercise 3.1, Solution 17:
P
= $1,280,000,
R
= 111% = 1.11,
1,280,000
=
1.11
P
B =
R
= $1,153,153.153.
..
Therefore, they budgeted $1,153,153.15 to build the highway.
Exercise 3.1, Solution 19:
a.
B
= 300,000,
R
= 12.25% = 0.1225,
P
= 300,000
0.1225 = 36,750
Therefore, 36,750 were from China.
b.
B
= 300,000,
R
= 9.75% = 0.0975,
P
= 300,000
0.0975 = 29,250
Therefore, 29,250 were from Philippines.
Combined number of immigrants from China and Philippines = 36,750 + 29,250 = 66,000
R
= 0.195% = 0.00195,
P
= 66,000,
66,000
=
0.00195
P
B =
R
= 33,846,153.85
Therefore, the population of Canada in 2010 was 33,846,154
Exercise 3.1, Solution 21:
Cost of labour = 0.30
30,000 = $9000.00
Increase amount = 5% of 9000 = $450.00
Therefore, cost of the car will increase by $450.00.
Exercise 3.1, Solution 23:
Increase amount for Tudor’s salary = 0.14
2815 = $394.10
Therefore, Tudor’s increased salary = $2815 + $394.10 = $3209.10
Increase amount for Rani’s salary = 0.11
2875 = $316.25
Therefore, Rani’s increased salary = $2875 + $316.25 = $3191.25
Therefore, Tudor has a higher salary after the yearly appraisal.