QuizSolnsThruQ16

QuizSolnsThruQ16 - (Quiz 01 was simply attendance on the...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: (Quiz 01 was simply attendance on the first day.) First find |E|=kQ/r . This requires finding r = (x + y ) = (8 + 6 ) = 100 = 10 . So |E| = -kQ/100 . (Note that Q has been replaced with -Q as specified. Next, E x = |E|(x/r) = (-kQ/100)(-8/10) = +8kQ/1000 = kQ/125 , and E y = |E|(y/r) = (-kQ/100)(6/10) = -3kQ/500 . Finally, E = x E x + y E y , so E = x kQ/125 + y 3kQ/500 . The volumetric charge distribution is given by = Q/ V . The volume of a sphere is given by V =(4/3) r = (4/3) 2 = (32/3) . So = 16 /(32/3) = 163/32 = 3/2 = 1.5C/m . Gausss law is E = Q in / A . The radius of the point of interest is less than the physical radius of the object, so the smaller value is used in getting Q in . Q in = V in this case where V = r l for a cylinder. So V = 3 l = 9 l , which means Q in = (-2)(9 l ) = -18 l . The area A always uses the radius for the point of interest ( Gaussian surface )....
View Full Document

This note was uploaded on 04/05/2012 for the course PHYS 131 taught by Professor Tibbets during the Spring '11 term at Cuyamaca College.

Page1 / 15

QuizSolnsThruQ16 - (Quiz 01 was simply attendance on the...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online