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Unformatted text preview: (Quiz 01 was simply attendance on the first day.) First find E=kQ/r . This requires finding r = (x + y ) = (8 + 6 ) = 100 = 10 . So E = kQ/100 . (Note that Q has been replaced with Q as specified. Next, E x = E(x/r) = (kQ/100)(8/10) = +8kQ/1000 = kQ/125 , and E y = E(y/r) = (kQ/100)(6/10) = 3kQ/500 . Finally, E = x E x + y E y , so E = x kQ/125 + y 3kQ/500 . The volumetric charge distribution is given by = Q/ V . The volume of a sphere is given by V =(4/3) r = (4/3) 2 = (32/3) . So = 16 /(32/3) = 163/32 = 3/2 = 1.5C/m . Gausss law is E = Q in / A . The radius of the point of interest is less than the physical radius of the object, so the smaller value is used in getting Q in . Q in = V in this case where V = r l for a cylinder. So V = 3 l = 9 l , which means Q in = (2)(9 l ) = 18 l . The area A always uses the radius for the point of interest ( Gaussian surface )....
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This note was uploaded on 04/05/2012 for the course PHYS 131 taught by Professor Tibbets during the Spring '11 term at Cuyamaca College.
 Spring '11
 Tibbets

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