Extra Problem 3 - Probability Rules - B A P = B P B = ∩ B...

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EMGT 269 – Elements of Problem Solving and Decision Making Question by Instructor: Dr. J. Rene van Dorp EXTRA PROBLEM 3: PROBABILITY CALCULUS 68 . 0 ) ( = A P 30 . 0 ) | ( = A B P 02 . 0 ) | ( = A B P 1. Find ) ( A P , ) ( B A P , ) ( B A P 2. Use your results under 1 and complete the following probability table A A B ? ) ( = B A P ? ) ( =
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Unformatted text preview: B A P ? ) ( = B P B ? ) ( = ∩ B A P ? ) ( = ∩ B A P ? ) ( = B P 68 . ) ( = A P ? ) ( = A P 1 3. Now use the table to find the following: ) | ( A B P , ) | ( A B P , ) | ( B A P , ) | ( B A P , ) | ( B A P , ) | ( B A P ....
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This note was uploaded on 04/04/2012 for the course CIVIL ENG CIV 125 taught by Professor Prof.chang during the Summer '11 term at International School of Management, New York.

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