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ENME 392 - Homework 5 Solutions - Sp12

# ENME 392 - Homework 5 Solutions - Sp12 - ENME392 Spring...

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Unformatted text preview: ENME392 Spring 2012 Homework 5 Solutions Total number of points: 100 Assignment: 1. Chapter 8 : 8.22 (5 pts) (a) the mean and standard deviation of the sampling distribution g G ¡ = ¢£¤.¥ cm ¦ G ¡ = § u¨ ¦ = § u©ª 6.9 = «.¬ ª = 1.38 ≈ ¢.¤ cm (b) The number of sample means that fall between 172.5 and 175.8 cm: ­®172.5 < ¯ ¡ < 175.8° ± § = ¯ ¡ − g G ¡ ¦ G ¡ = 172.5 − 174.5 1.4 = −1.4492, ­®² < −1.4492° = 0.0668 ± © = ¯ ¡ − g G ¡ ¦ G ¡ = 175.8 − 174.5 1.4 = 0.7491, ­®² < 0.7491° = 0.8159 ­®172.5 < ¯ ¡ < 175.8° = 0.8159 − 0.0668 = ³.£¤´¢ 200 × ­®172.5 < ¯ ¡ < 175.8° = 200 × 0.7491 = 149.82 ≈ ¢¥³ mean samples (c) the number of sample means falling below 172.0 cm. ­®¯ ¡ < 172° = ­ µ² < 172 − 174.5 1.4 ¶ = ­®² < −1.8116° = 0.0359 200 × ­®² < −1.8116° = 200 × 0.0359 = 7.18 ≈ · samples 2. Chapter 8 : 8.24 (10 pts) Sample size : n = 36 Mean: g G ¡ = 40 ohms SD : ¦ = 2 ohms Sample S.D. : ¦ G ¡ = § u¨ ¦ = § u¸« 2 = © « = § ¸ The probability that a random sample of 36 resistors will have a combined resistance of 1458...
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