Comp sci midterm 2

Comp sci midterm 2 - 03:13 Compscimidterm2:...

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03:13 Comp sci midterm 2: Page memory technique: logical address of 2566 with page size of 1024, corresponds to the 518th byte of page 2  of process 2566/1024= 2.5058  Page=2 (can have 2 full pages) offset: 1024*0.5058= 518  <page, offset>-------------<2,518> therefore: logical address/page size = take note of integer, then calculate the  remainder. offset. to convert to physical address: take ex. <1, 222> page size of 1024 we look up page on pmt to corresponding Frame. ...take frame*size of page+ offset so ex. page 1 of process one is 12 frames. ..
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therefore: 12*1024+222=1250 page size corresponds to frame size: identically sized frame. each page has a corresponding frame number SQL:  Selection: across row Project: across column Join:                    sql joins the the two and uses it as its “Select” and project depeding on  the conditions we specifies.  Select removing moving, rating = R that is a project  -CREATES A NEW TABLE % SIGNS MEAN WHITE SPACES However, multiprogramming requires a pre-emptive strategy. Can you think of a reason
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Comp sci midterm 2 - 03:13 Compscimidterm2:...

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