Lecture_20_2007

Lecture_20_2007 - Lecture 19 in a nutshell f i F t = ∆ p...

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Unformatted text preview: Lecture 19 in a nutshell f i F t- = ∆ p p F t impulse ∆ = m = υ Momentum = P Units kgm/s momentum is a vector 1 2 1 2 f f i i + = + p p p p During collisions, total final momentum=total initial momentum There are three types of collision Elastic KE is conserved Inelastic KE is lost Completely Inelastic or sometimes “ perfectly inelastic “ KE is lost, because the objects stick together In other words if objects stick together KE must be lost Conservation of momentum on 2D Momentum is conserved in 2D We just have to find the components of momentum in the x and y directions A 1000kg car moving at 15m/s is driving east and collides with a 3000kg truck driving north at 10m/s. The vehicles lock together . Q. What is the final direction and velocity Conservation of momentum on 2D A 1000kg car moving at 15m/s is driving east and collides with a 3000kg truck driving north at 10m/s. The vehicles lock together . Q. What is the final direction and velocity 1 15 / i m s = υ 2 10 / i m s = υ 12 f υ θ 1 m 2 m 1 2 m m + N/y E/x Total P East initial 1 1 2 2 ix ix m m + υ υ 1 1 i m = υ Total P East final ( 29 1 2 12 cos f m m θ + υ Total P North initial 1 1 2 2 iy iy m m + υ υ 2 2 i m = υ Total P North final ( 29 1 2 12 sin f m m θ + υ Conservation of momentum on 2D A 1000kg car moving at 15m/s is driving east and collides with a 3000kg truck driving north at 10m/s. The vehicles lock together ....
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This note was uploaded on 04/07/2012 for the course PHYS 111 taught by Professor Dr.jackman during the Fall '07 term at Waterloo.

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Lecture_20_2007 - Lecture 19 in a nutshell f i F t = ∆ p...

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