{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Lecture_32web_2007

This preview shows pages 1–6. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Quiet please ladies and gentlemen The lecture is about to begin n Statics/Equilibrium For an object to be static it is necessary for: the net force on an object to be zero And the net torque on the object is zero x F = ∑ τ = ∑ We can use these three conditions to find the forces at different points on an object in equilibrium y F = ∑ A Printing press of mass 15,000kg sits on top of a wooden beam its centre of mass is 5m from the end of the beam. The beam is 20m long and has a mass of 1500kg, it sits on two uprights. What are the forces F1 and F2 on the beam due to the uprights Statics/Equilibrium 1500 g 15000 g 10 m 5 m 5 m 1 F 2 F Find F1 and F2 Statics/Equilibrium 1500 g 15000 g 10 m 5 m 5 m 1 F 2 F y F = ∑ ( 29 1 2 1500 15000 0 1 F F g g + - - = +ve 2 12000 F g = 1 12000 1500 15000 0 F g g g + - - = 1 1500 15000 12000 F g g g = + - 1 4500 F g = Find F1 and F2 Statics/Equilibrium 1500 g 15000 g 10 m 5 m 5 m 1 F 2 F y F = ∑ ( 29 1 2 1500 15000 0 1 F F g g + - - = x F = ∑ We can calculate the torque around any point on the object and it must be zero We must decide where, the pivot point is, and which direction of torque is...
View Full Document

{[ snackBarMessage ]}