This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: cable at the middle must be half the weight, 2 / w . Equivalently, the net force on the upper half of the cable must be zero. From part (a) the tension at the top is w , the weight of the top half is 2 / w and so the tension in the cable at the middle must be 2 / 2 / w w w =-. d) A graph of T vs. distance will be a negatively sloped line....
View Full Document