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Unformatted text preview: hanna (brh687) – hk 14 – Opyrchal – (11105) 1 This printout should have 5 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A body oscillates with simple harmonic mo tion along the xaxis. Its displacement varies with time according to the equation x ( t ) = A sin( ω t + φ ) . If A = 5 m, ω = 3 . 477 rad / s, and φ = 1 . 0472 rad, what is the acceleration of the body at t = 4 s? Note: The argument of the sine function is in radians rather than degrees. Correct answer: 41 . 3256 m / s 2 . Explanation: Let : A = 5 m , ω = 3 . 477 rad / s , φ = 1 . 0472 rad , and t = 4 s . x = A sin( ω t + φ ) v = d x dt = ω A cos( ω t + φ ) a = d v dt = ω 2 A sin( ω t + φ ) = ω 2 A sin( ω t + φ ) = (3 . 477 rad / s) 2 (5 m) × sin[(3 . 477 rad / s)(4 s) + 1 . 0472 rad] = 41 . 3256 m / s 2 . 002 10.0 points Military specifications often call for electronic devices to be able to withstand accelerations...
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This note was uploaded on 04/07/2012 for the course PHYSICS 121 taught by Professor James during the Spring '12 term at University of Texas.
 Spring '12
 James
 Physics, Simple Harmonic Motion

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