EE321 Spring 2010
Homework 2
Problems 1 – UI Inductor Analysis
Consider the UI core shown in Figure 1.41 (or Lecture Set 1, slide 34).
Consider
the following parameters:
1
=
w
cm;
5
=
s
w
cm;
2
=
s
d
cm;
5
=
d
cm;
1
=
g
mm;
100
=
N
.
Suppose the material used is such that for a flux density less than 1.3 T (the saturation
point), the magnetic material is linear and has a permeability 1500 times that of free
space (i.e. a relative permeability of 1500).
What is the inductance of the UI core ?
Consider your results from Problem 5.
For the current level that yields a flux density of 1.3 T, what will be the energy stored in
the inductor.
Recompute the inductance of the core, that current that will result in a flux
density of 1.3 T, and the energy stored in the core if the airgap is removed.
This
example illustrates why inductors utilize an air gap.
Note: along these lines, it worth
noting that energy density at any point is the dot product of the field intensity and the flux
density.
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 Spring '08
 Staff
 Magnetic Field, Inductor, Energy density, magnetic material, Self Inductance

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