{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

ENME392 HW6 - The square is 3.5 inches by 3.5 inches...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Natalie Jones Homework 6 ENME392 11 October 2011 I pledge on my honor that I have not given nor received any unauthorized assistance on this assignment. E) The three curves all roughly follow the anticipated binomial probability distribution, though as the number of iterations increases the experimental probability distribution more closely follows the binomial probability distribution. This is to be expected, as we expect that as the number of trials increases the distribution will more closely follow the binomial probability distribution. G) We expect the number of coins that fall in the square to follow a distribution according to the area of the square versus the area of the box. The box is 12 inches by 9 inches, resulting in 108 square inches of area.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: The square is 3.5 inches by 3.5 inches, resulting in 12.25 square inches of space in which the coins can fall in and be considered a “success.” Therefore, we anticipate that 11.34% of the coins will fall in the area [(12.25/108)*100%]. Of the twenty coin trial, the expected value is therefore 2.27 coins per trial landing in the square [0.1134*20]. H) The probability distribution was calculated using the theory above and the binomial probability distribution formula in which: X = number of coins in square N = 20 (number of trials) P = (12.25 in^2/108 in^2) = 0.1134 Q = (1-0.1134) = 0.8866 (N!)/(X!*(N-X)!)*((P)^X)*((Q)^(N-X)) I) The plot of the expected probability distribution follows the expected binomial probability distribution....
View Full Document

{[ snackBarMessage ]}