106-19992-MT2

# 106-19992-MT2 - ﬂ 5 PROBLEM[I(25 points In the circuit...

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Unformatted text preview: ﬂ 5 ' ' PROBLEM [I] (25 points) In the circuit MOW, the capacitor C is initially uncharged and the switch 3 is closed at time I = D. I 2:: 4:: 1:: 16V 33— av C-SFF (:1) Find the currenlfjust aﬁerthe switchSis closed. \ m [an]: 31.4.. ﬁr ”nu, Igor 4:15:de Aihule£=g Mmpagihritg unchanged. 1 qu+lij+aI—Ié=a TWL I‘L bEhME-‘I M a ghort’ Circuit .} 5'1; +LfI"=fE [email protected] .1"- e d I + w E ll—E’HG ----- C2) _ I. Selma. ﬁrm-G) Md®ﬁr1 a h C. lle. {Mkd i n+1 :95 I" II I =l+ﬂ "Ml“; ﬁH-QMIMF mtdfn I's +5 + 1f1)+2(1‘}——i£=0 3I=10 ll clg-Jq =5r33ﬁ‘ ..__.___—J {c} Find the potential difference ms the capacitor and detcnninn which plate, upper or lower, is at higher potential at time I = I». Tim- bop esp» ﬁ-rmw a594,; gnaw milk V£+H£¢3+2T~-|L=O 43-May FmthJwtﬁ-ké Nit-1- 1(1§)-IL=0 Vc=vw_vm”=+ﬁ-3v - 2. w; m- ig- _ {- V urn”... >v....... ”iv—W 91.1 W .- M'- Phys 106%}.an 9mm my 13.2000 D 6 PROBLEM (2) (25 points) A reetangnlarloop of wire with dimensions It} em 5 cm. liea' In the 3}- lane. It carries a current of 200 A' In the direction ahewn' 1n the ﬁgure. A on orm magnetic ﬁeld, ={DJ} + 0. 2k) T exists intheapacearoundtheloop. . z Wheat-PM Weak-w. 1:290 ﬁt A: guanine-4:90“; M:I’ 5 em ‘9' (a) ﬁnd the net magnetic force on the loop,‘ In vector fonn (in terms of unit vectors} RM Maumlﬁ’aei‘lH' a: at“?! we ”EM Fiﬁ" at .5 MA Fb¢=_E:A ' maﬁa. -- Low. I5» emawmmmw 1 LIZ-'0 W3”? Mglrt‘ﬁhummiunﬂﬂk fem. re mo {h} Find the torque on the loop, in vectorfonn (in terms of unit vectors) A worm 10410 In a. MW; dipole wi-lanat-aiacdipelemm Uﬂcﬁ'Wﬂ 544mm ﬂ=lql= Mer‘l M4 (“#31 wild-Uta mint-1m! uedor -hmfmﬂfmmtf Md wgmMr'ski WW5 "1‘3"" {Md—M‘ ﬁt: MM (—11) = (4}{290A){50K1e"fu th- 1,) = ‘K 1‘“ Fe? e; =(E anthem; +n.zL)-rj=—e-'5 Exjwm Mfr—l "-5 _L II E. 0*5315 ”IN (c) Find the magnetic potential energy,r of the loop. Mt-ju-B —--(— 1a.») [(03J+enzh1'r3= 9'1“" E53 H Phys roe Seeom' Menu Page ere May 13. zone _ 0.7 -,-. : PROBLEM [3) (25 points) A thin, ini‘initteljir long wire C ing acurrent I. is bent as shown in the ﬁgure, with all sections lying in the plane of th: 5:. 111d that magnitude and direction of the magnetic ﬁeld at the c'hhter of the circular arc of nus R. and of central angle of 135‘. (You may us: the derived formulas direﬂiy.) . I . Bi"! = E’h = L 3 "Li" NW3: r—mR _ I . ,_ . 1-.” W -&*——i’— WWW ; M «w a- «r Suing-liking ﬁrm magmatic Freed a: pom c, weﬁéd in B. = f": I {MO I it?) pi = gun: 3 I '1 'mR + Him. +41%? mm. + '42:? .. I .' Br." 52?: (hi'i'r— 1'43?) III-1+9 43:1?an .2. (if: F: 4’ HER :3 1'?- I B; -- ﬁ— 3 1-149 m Page. Mﬁ.‘ Mam um. M Bigt_5amlr~t I” as: 1% Elm—.9, r1. “hike. 'hu. int-gm! B 1-de War-4M; 5.4% wt}! M4 ‘Fl'ﬂd 5: ' Phys I06 Second Midterm Page 5m May M, 2m: PROBLEM (4} {25 points} Two long cylindrical solid wires of radius R are in oonmet along their full length, as shown in Figure I The wires eerryeq equal and uniformly distributed current: I III the +x direction (out of the page in Figure lIJ Using Ampere '5 law and superposition. ﬁnd the magnitude and direction of the eldtaJ at point A and (h) at pointB (Give your results In terms of unit vectors. J magnetiei 08 AJPE'LAE lam“ : WM jimﬁqmasneﬂr. 15214 if POM‘tﬂ M WM B. 15 death "he. upper.31's @49le mm;- éat'di :ﬂal ding“; Bllznf)=ﬁlﬂt MPHQSR We I—i éb}. 45 mfg]: {Hg —" G {IMP} It MUM r“ 2|5£ ICHC.‘ I .4 _ -t he __ ”OI .." I _.e _ ﬁgtt’jl +J.) EE' Eli-61.. inlet“; (J)+ ”gang-J) "R ('1’. f r d :1” g1 _A i H 56 331%“) Phys Immum engines my memo ...
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