problem04_52

University Physics with Modern Physics with Mastering Physics (11th Edition)

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4.52: a) = m mass of one link The downward forces of magnitude 2 ma and ma for the top and middle links are the reaction forces to the upward force needed to accelerate the links below. b) (i) The weight of each link is N 94 . 2 ) s / m 80 . 9 )( kg 300 . 0 ( 2 = = mg . Using the free- body diagram for the whole chain: 2 2 net s / m 5 . 3 or s / m 53 . 3 kg
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Unformatted text preview: 900 . N 18 . 3 kg 900 . ) N 94 . 2 ( 3 N 12 3 = =-= = m F a (ii) The second link also accelerates at 2 s / m 53 . 3 , so: ma mg ma F F =--= 2 top net ) N 94 . 2 ( 2 ) s / m 53 . 3 )( kg 300 . ( 2 2 2 2 top + = + = mg ma F N . 8 N 88 . 5 N 12 . 2 = + =...
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This document was uploaded on 02/04/2008.

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