HW2 - MSE Section 2 Chapter 2 # 31, 36, 37, 43, 52, 64 and...

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MSE Section 2 Chapter 2 # 31, 36, 37, 43, 52, 64 and Chapter 3 #6, 7, 8, 10, 14, 15, 19, 20, 22 31. Ionic bonding - result from electrostatic attraction of oppositely charged ions; nondirectional bond Covalent bonding - result from the sharing of electrons; directional bond; involves the overlapping of half-filled orbitals of two atoms (most cases) Metallic bonding -result from the sharing of delocalized outer electrons in the form of an electron charge cloud by an aggregate of metal atoms; nondirectional bond 36. After ionization, why is the chloride ion larger than the chlorine atom? The chloride ion gains an electron making a larger radius, thus a larger ion. The chlorine atom’s loss of electron causes the radius to decrease, thus getting smaller. 37. Calculate attractive force: F attractive = - Z1Z2e4πϵ0a2 Z 1 , Z 2 = number of electrons removed or added from the atoms during the ion formation= +1 for K + , -1 for Br - E = electron charge = 1.60 x 10 -19 C A = interionic separation distance = sum of the radii of K
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This note was uploaded on 04/07/2008 for the course MSE 150 taught by Professor Wittig during the Spring '07 term at Vanderbilt.

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HW2 - MSE Section 2 Chapter 2 # 31, 36, 37, 43, 52, 64 and...

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