Midterm2W09 Key

Midterm2W09 Key - Chem6AL Russak 2March2009 Midterm2 ..You...

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Chem 6AL Russak 2 March 2009 Midterm 2 The following questions are all multiple choice. Please fill out the score sheet with your name. You must put your perm number on the score sheet and fill in the bubbles associated with it to receive credit for the exam. There are equations on the back sheet that you may need to calculate your answers. You may use a calculator. There is only 1 correct choice for each question, filling in multiple answers will result in no credit given. 1. Infrared Spectroscopy is useful for: a. Differentiation of molecules of same functional group b. Differentiation of molecules of differing functional groups c. Determining the yield of a product d. Determining non equivalent protons e. None of the above 2. What type of stretching gives rise to peaks in the IR? a. Asymmetric b. Symmetric c. Bending d. Twisting e. None of the above 3. The region of an IR from 1500 cm 1 to 400 cm 1 is known as: a. The shortwave region b. The high energy region c. The spectral region d. The fingerprint region e. None of the above 4. An IR was taken of a compound that displayed a strong peak at 1700 cm 1 and a small peak at 3400 cm 1 . The small peak is most likely due to a. The presence of an OH stretch from a primary alcohol b. The presence of an NH stretch from an amino group c. The presence of an overtone d. The presence of a carbonyl stretch and an sp 2 hybridized C H stretch 5. The position of a carbonyl stretch is proportional to the a. Type of functional group b. The bond order c. The bond length d. The bond strength e. None of the above
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6. What can be said about Energy and IR? a. Energy is proportional to wavenumber b. Energy is proportional to wavelength c. Energy increases from left to right on the IR spectrum d. The intensity of the peaks is directly related to the energy e. None of the above For the following questions, match the compound below to the IR spectra (the letter of the compound will be the answer for that questions’ spectra. 7. Answer = D This has to be D because the C=O stretch is too high to be a regular ketone(compound E) or an ester (compound C) and also lacks a strong C O stretch at 1250. This is D and not E because D has RING STRAIN which increases the bond order and the frequency of the C=O peak. 8. Answer = E
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9. Answer = A This compound has sp 2 C H stretching…so only compound it could be is A 10. Answer = B 11. Answer = C This is answer C because of the strong C O stretch at 1250. This should be the determining factor between either D or E.
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12. How did sealing the melting point tube help prevent sublimation before melting of caffeine in experiment 4?
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Midterm2W09 Key - Chem6AL Russak 2March2009 Midterm2 ..You...

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