problem05_20

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
5.20: Similar to Exercise 5.16, the angle is ), arcsin( 2 2 gt L , but here the time is found in terms of velocity along the table, x t v x , 0 = being the length of the table and 0 v the velocity component along the table. Then, ( 29 ( 29 . 38 . 1 m) 75 . 1 ( s m 80
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: . 9 s) m m)(3.80 10 50 . 2 ( 2 arcsin 2 arcsin 2 arcsin 2 2 2 2 2 2 2 = = = -gx Lv v x g L...
View Full Document

This document was uploaded on 02/04/2008.

Ask a homework question - tutors are online