**Unformatted text preview: **C is N, 31.0 ) 36.9 (0.35)cos 36.9 N)(sin (25.0 N 9 ) 9 . 36 cos 9 . 36 (sin N 9 k = ° + ° + = ° + ° + = μ B C w w or 31 N to two figures. The intermediate calculation of the first tension may be avoided to obtain the answer in terms of the common weight w of blocks A and B , )), cos (sin ( k k θ θ μ w w C + + = giving the same result. (d) Applying Newton’s Second Law to the remaining masses ( B and C ) gives : ( 29 . s m 54 . 1 ) sin cos ( 2 k = + θ-μ-= c B B B c w w w θ w w g a...

View
Full Document

- '
- NoProfessor
- Force