hw1-solutions

Notice that this part is for the first application

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Unformatted text preview: be .8 * .4 for the first application plus .2 * .99 for the second application. CSCE 4610/5610 Assignment 1 Answers 5 Speedup = 1 / ( (1 (.8 * .4 + .2 * .99)) + (.8 * .4 + .2 * .99) / 2) = 1.35 CSCE 4610/5610 Assignment 1 Answers 6...
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This note was uploaded on 05/21/2012 for the course CSCE 4610 taught by Professor Kavi during the Spring '12 term at North Texas.

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