hw1-solutions

The fourth edition uses the same equation that was

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: edition text. I did not deduct points for using this equation with any assumed N value from 11.5 to 15.5) DY = (1 + .75 * 1.99 / 4) ^ -4 = 0.2813 Note the use of 1.99 cm2 representing 1 core of size 199 mm2 If you assumed two cores fitting into a single 199 mm2 die, the equation is: DY = (1 + .75 * 0.995 / 4) ^ -4 = 0.5045 In this case, the DY is the probability that 1 core is good. There are 2 ways to find the yield for a dual core chip. The probability of both cores being good, plus the probability of core A being good while core B is bad, plus the probability of core A being bad while core B is good. Alternately, you can use 1 the probability of both cores being bad. First approach: P * P (both good) + P * (1 P) (A good, B bad) + (1-P) * P (A bad, B good) 0.2813 * 0.2813 + 2 * (1 0.2813) * 0.2813 = 0.4835 Second approach: 1 ((1 P) (A bad) * (1 P) (B bad)) 1 (1 0.2813) * (1 0.2813) = 1 (.7187) ^ 2 = 0.4835 If you assumed both cores fit into a single 199 mm2 die the probability of at least 1 good core is 0.7545 CSCE 4610...
View Full Document

This note was uploaded on 05/21/2012 for the course CSCE 4610 taught by Professor Kavi during the Spring '12 term at North Texas.

Ask a homework question - tutors are online