problem05_50

University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.50: a) . s m 5.24 s) (60.0 m) 0 . 50 ( 2 2 = π = π T R b) The magnitude of the radial force is N 49 ) 4 ( 4 2 2 2 2 2 = = = gT R w T R m R mv π (to the nearest Newton), so the apparent weight at the top is N, 833 N 49 N 882 = - and at the bottom is N 931 N 49 N 882 = + . c) For apparent weightlessness, the radial acceleration at the top is equal to
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This document was uploaded on 02/04/2008.

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