University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.60: a) The tension in the cord must be 2 m g in order that the hanging block move at constant speed. This tension must overcome friction and the component of the gravitational force along the incline, so ( 29 α + α = cos sin 1 1 2 g m μ g m g m k and ) cos (sin 1 2 α k μ m m + = . b) In this case, the friction force acts in the same direction as the tension on the block
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Unformatted text preview: of mass 1 m , so ) cos sin ( 1 k 1 2 α g m μ α g m g m-= , or ) cos α (sin k 1 2 μ m m-= . c) Similar to the analysis of parts (a) and (b), the largest 2 m could be is 1 s (sin cos ) m μ + and the smallest 2 m could be is 1 s (sin cos ) m-....
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This document was uploaded on 02/04/2008.

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