problem05_61

University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.61: For an angle of ° 0 . 45 , the tensions in the horizontal and vertical wires will be the same. a) The tension in the vertical wire will be equal to the weight N 0 . 12 = w ; this must be the tension in the horizontal wire, and hence the friction force on block
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Unformatted text preview: A is also 12.0 N . b) The maximum frictional force is N 15 N) . 60 )( 25 . ( s = = A w μ ; this will be the tension in both the horizontal and vertical parts of the wire, so the maximum weight is 15 N....
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This document was uploaded on 02/04/2008.

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