Lecture 21-Acid bases

# What is the concentraton of this soluton two step

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Unformatted text preview: n •  Symbol M ConcentraTon number of moles (mol) n C = __ V volume (L) •  The units are moles per litre (mol L ­1 or M) Example •  A student prepared a soluTon of NaCl by dissolving 1.461 g of NaCl in a 250.00 mL volumetric ﬂask to study the eﬀect of dissolved salt on the rusTng of an iron sample. What is the concentraTon of this soluTon? Two step process: 1.  Calculate how many moles in 1.461g of NaCl: 1 mole of NaCl is (23+35.5) = 58.5 g mol ­1 So 1.461 g = 1.461 g/58.5 g mol ­1 = 0.02 moles Example •  Second step: –  dissolving 1.461g (0.02 moles) of NaCl in a 250.00 mL volumetric ﬂask. 2. The concentraTon of this soluTon c...
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## This note was uploaded on 05/28/2012 for the course CHEM 101 taught by Professor Ooo during the Spring '12 term at University of West Alabama-Livingston.

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