Alg_Complete

# 2 5 5 4 5 20 20 ok in this case 20 is

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Unformatted text preview: fies the equation. [Return to Problems] (b) So, we want to see if y = 8 satisfies the equation. First plug the value into the equation. 3 ( 8 + 1) = 4 ( 8) - 5 ? 27 = 27 OK So, y = 8 satisfies the equation and so is a solution. [Return to Problems] (c) In this case we’ve got an inequality and in this case “satisfy” means something slightly different. In this case we will say that a number will satisfy the inequality if, after plugging it in, we get a true inequality as a result. Let’s check z = 1 . ? 2 (1 - 5 ) £ 4 (1) -8 £ 4 OK So, -8 is less than or equal to 4 (in fact it’s less than) and so we have a true inequality. Therefore z = 1 will satisfy the inequality and hence is a solution [Return to Problems] © 2007 Paul Dawkins 59 http://tutorial.math.lamar.edu/terms.aspx College Algebra (d) This is the same inequality with a different value so let’s check that. ? 2 ( -5 - 5 ) £ 4 ( -5 ) - 20 £ -20 OK In this case -20 is less than or equal to -20 (in this case it’s equal) and so again we get a true inequa...
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## This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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