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Unformatted text preview: rue inequality. This means that our
solutions will, in most cases, be inequalities themselves. Example 1 Solving the following inequalities. Give both inequality and interval notation forms
of the solution.
(a) -2 ( m - 3) < 5 ( m + 1) - 12 [Solution]
(b) 2 (1 - x ) + 5 £ 3 ( 2 x - 1) [Solution]
Solving single linear inequalities follow pretty much the same process for solving linear
equations. We will simplify both sides, get all the terms with the variable on one side and the
numbers on the other side, and then multiply/divide both sides by the coefficient of the variable to
get the solution. The one thing that you’ve got to remember is that if you multiply/divide by a
negative number then switch the direction of the inequality.
© 2007 Paul Dawkins 124 http://tutorial.math.lamar.edu/terms.aspx College Algebra (a) -2 ( m - 3) < 5 ( m + 1) - 12
There really isn’t much to do here other than follow the process outlined above. -2 ( m - 3) < 5 ( m + 1) - 12
-2m + 6 < 5m + 5 - 12
-7m < -13
7 You d...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12