Alg_Complete

# 0 x2 4x 4 0 x 2 2 x 2 sure enough there

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Unformatted text preview: 2 + 4 This one is actually a fairly simple one to graph. We’ll first notice that it will open upwards. Now, the vertex is probably the point where most students run into trouble here. Since we have x2 by itself this means that we must have h = 0 and so the vertex is ( 0, 4 ) . Note that this means there will not be any x-intercepts with this parabola since the vertex is above the x-axis and the parabola opens upwards. Next, the y-intercept is, h ( 0) = ( 0) + 4 = 4 y - intercept : ( 0, 4 ) 2 The y-intercept is exactly the same as the vertex. This will happen on occasion so we shouldn’t get too worried about it when that happens. Although this will mean that we aren’t going to be able to use the y-intercept to find a second point on the other side of the vertex this time. In fact, we don’t even have a point yet that isn’t the vertex! © 2007 Paul Dawkins 210 http://tutorial.math.lamar.edu/terms.aspx College Algebra So, we’ll need to find a point on either side of the vertex. In this case since the function isn’t too bad we’ll just plug in a couple of poi...
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## This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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