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Unformatted text preview: case it looks like we are shifting f ( x ) = x3 . We can then see that, h ( x ) = ( x + 2) = f ( x + 2)
3 © 2007 Paul Dawkins 228 http://tutorial.math.lamar.edu/terms.aspx College Algebra In this case c = 2 and so we’re going to shift the graph of f ( x ) = x3 (the dotted line on the
graph below) and move it 2 units to the left. This will mean subtracting 2 from the x coordinates
of all the points on f ( x ) = x3 .
Here is the graph for this problem. [Return to Problems] (b) g ( x ) = x-4 In this case it looks like the base function is x and it also looks like c = -4 and so we will be shifting the graph of x (the dotted line on the graph below) to the right by 4 units. In terms of
coordinates this will mean that we’re going to add 4 onto the x coordinate of all the points on x.
Here is the sketch for this function. [Return to Problems] Vertical and Horizontal Shifts
Now we can also combine the two shifts we just got done looking at into a single problem. If we
know the graph of f ( x ) the graph of g ( x ) = f ( x + c ) + k...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12