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Unformatted text preview: (c) ln xy
For this part let’s first rewrite the logarithm a little so that we can see the first step.
1 ln xy = ln ( xy ) 2
Written in this form we can see that there is a single exponent on the whole term and so we’ll take
care of that first. ln xy = 1
ln ( xy )
2 Now, we will take care of the product. 1
( ln x + ln y )
Notice the parenthesis in this the answer. The
multiplies the original logarithm and so it will
ln xy = also need to multiply the whole “simplified” logarithm. Therefore, we need to have a set of
parenthesis there to make sure that this is taken care of correctly.
[Return to Problems] æ ( x + y )2 ö
(d) log 3 ç 2
ç x + y2 ÷
We’ll first take care of the quotient in this logarithm. æ ( x + y )2 ö
log 3 ç 2
÷ = log 3 ( x + y ) - log 3 ( x 2 + y 2 )
ç x +y ÷
We now reach the real point to this problem. The second logarithm is as simplified as we can
make it. Remember that we can’t break up a log of a sum or difference and so t...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12