Again the ln2 and ln3 are just numbers and so the

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Unformatted text preview: e recall our exponent properties we can fix this however. 3z = 32( z + 5) We now have the same base and a single exponent on each base so we can use the property and set the exponents equal. Doing this gives, z = 2 ( z + 5) z = 2 z + 10 -10 = z So, after all that work we get a solution of z = -10 . [Return to Problems] (d) 45-9 x = 1 8 x -2 In this part we’ve got some issues with both sides. First the right side is a fraction and the left side isn’t. That is not the problem that it might appear to be however, so for a second let’s ignore that. The real issue here is that we can’t write 8 as a power of 4 and we can’t write 4 as a power of 8 as we did in the previous part. The first thing to do in this problem is to get the same base on both sides and to so that we’ll have to note that we can write both 4 and 8 as a power of 2. So let’s do that. (2 ) 2 5 -9 x = 2 2( 5- 9 x ) = 1 (2 ) 3 x -2 1 3( x - 2 ) 2 It’s now time to take care of the fraction on the right side. To do t...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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