Although with that said this one is really nothing

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: traight to the final form of this and leave the details to you to check. [Return to Problems] (b) 9 x 6 This radical violates the second simplification rule since both the index and the exponent have a common factor of 3. To fix this all we need to do is convert the radical to exponent form do some simplification and then convert back to radical form. © 2007 Paul Dawkins 19 http://tutorial.math.lamar.edu/terms.aspx College Algebra 9 6 1 2 1 x6 = ( x6 ) 9 = x 9 = x 3 = ( x2 )3 = 3 x 2 [Return to Problems] (c) 18 x 6 y11 Now that we’ve got a couple of basic problems out of the way let’s work some harder ones. Although, with that said, this one is really nothing more than an extension of the first example. There is more than one term here but everything works in exactly the same fashion. We will break the radicand up into perfect squares times terms whose exponents are less than 2 (i.e. 1). 18 x 6 y11 = 9 x 6 y10 ( 2 y ) = 9 ( x3 ) 2 ( y ) (2 y) 52 Don’t forget to look for perfect squares in the number as we...
View Full Document

Ask a homework question - tutors are online