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Unformatted text preview: in the solution set.
Let’s take a look at some examples. Example 1 Solve each of the following equations.
(a) 3 ( x + 5 ) = 2 ( -6 - x ) - 2 x [Solution]
10 - y
2y - 6 y - 6y + 9
+ 2 [Solution]
z + 3 z - 10
In the following problems we will describe in detail the first problem and the leave most of the
explanation out of the following problems.
(a) 3 ( x + 5 ) = 2 ( -6 - x ) - 2 x
For this problem there are no fractions so we don’t need to worry about the first step in the
process. The next step tells to simplify both sides. So, we will clear out any parenthesis by
multiplying the numbers through and then combine like terms. 3 ( x + 5 ) = 2 ( -6 - x ) - 2 x
3 x + 15 = -12 - 2 x - 2 x
3 x + 15 = -12 - 4 x The next step is to get all the x’s on one side and all the numbers on the other side. Which side
the x’s go on is up to you and will probably vary with the problem. As a rule of thumb we will
usually put the variables on the sid...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12