Evaluating function is really nothing more than

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Unformatted text preview: we will get a single value from the multiplication. Likewise, we will only get a single value if we add 1 onto a number. Therefore, it seems plausible that based on the operations involved with plugging x into the equation that we will only get a single value of y out of the equation. So, this equation is a function. [Return to Problems] (b) y = x 2 + 1 Again, let’s plug in a couple of values of x and solve for y to see what happens. x = -1: y = ( -1) + 1 = 1 + 1 = 2 x = 3: y = ( 3) + 1 = 9 + 1 = 10 2 2 Now, let’s think a little bit about what we were doing with the evaluations. First we squared the value of x that we plugged in. When we square a number there will only be one possible value. We then add 1 onto this, but again, this will yield a single value. So, it seems like this equation is also a function. Note that it is okay to get the same y value for different x’s. For example, x = -3 : y = ( -3) + 1 = 9 + 1 = 10 2 We just can’t get more than one y out of the equation after we plug in the x. [Return to Problems] (c) y 2 = x + 1 As we’ve done with the previous two equations let’s plug in a couple of value of x, solve for y © 2007...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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