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Unformatted text preview: 5aR ) = m Finally, divide by the coefficient of b. Recall as well that the “coefficient” is all the stuff that
multiplies the b. Doing this gives, b= Example 4 Solve m
V + 5aR 111
= + for c.
First, multiply by the LCD, which is abc for this problem. 1
( abc ) = æ + ö ( abc )
bc = ac + ab
Next, collect all the c’s on one side (the right will probably be easiest here), factor a c out of the
terms and divide by the coefficient. bc - ac = ab c ( b - a ) = ab
c= © 2007 Paul Dawkins 83 ab
b-a http://tutorial.math.lamar.edu/terms.aspx College Algebra Example 5 Solve y = 4
5x - 9 Solution
First, we’ll need to clear the denominator. To do this we will multiply both sides by 5 x - 9 .
We’ll also clear out any parenthesis in the problem after we do the multiplication. y ( 5x - 9 ) = 4
5 xy - 9 y = 4 Now, we want to solve for x so that means that we need to get all terms without a y in them to the
other side. So add 9y to both sides and the divide by the coefficient of x. 5 xy = 9 y + 4
9y + 4
5y Example 6 Solve y = 4 - 3x
1 + 8x Soluti...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12