Here is that step for this part 7 log12 x 2 log12 y

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: e will assume that x > 0 and y > 0 . 5. log b ( xy ) = log b x + logb y 6. æxö log b ç ÷ = logb x - log b y è yø 7. log b ( x r ) = r log b x 8. If log b x = log b y then x = y . We won’t be doing anything with the final property in this section; it is here only for the sake of completeness. We will be looking at this property in detail in a couple of sections. The first two properties listed here can be a little confusing at first since on one side we’ve got a product or a quotient inside the logarithm and on the other side we’ve got a sum or difference of two logarithms. We will just need to be careful with these properties and make sure to use them correctly. Also, note that there are no rules on how to break up the logarithm of the sum or difference of two terms. To be clear about this let’s note the following, log b ( x + y ) ¹ log b x + log b y log b ( x - y ) ¹ log b x - logb y Be careful with these and do not try to use these as they simply aren’t true. © 2007 Paul Dawkins 290 http://tutorial.m...
View Full Document

This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

Ask a homework question - tutors are online