Unformatted text preview: ntercept of
the line, that’s the number without an x (including sign) and as discussed above we can use the
slope to find a second point on the line. At that point there isn’t anything to do other than sketch
(a) 2 y - 6 x = -2
First solve the equation for y. Remember that we solved equations like this back in the previous
chapter. 2 y = 6x - 2
y = 3x - 1 So, the slope for this line is 3 and the y-intercept is the point ( 0, -1) . Don’t forget to take the
sign when determining the y-intercept. Now, to find the second point we usually like the slope
written as a fraction to make it clear what the rise and run are. So, m=3= 3 rise
1 run Þ rise = 3, run = 1 The second point is then, x2 = 0 + 1 = 1 y 2 = -1 + 3 = 2 Þ (1, 2 ) Here is a sketch of the graph of the line. [Return to Problems] © 2007 Paul Dawkins 165 http://tutorial.math.lamar.edu/terms.aspx College Algebra (b) 3 y + 4 x = 6
Again, solve for y. 3 y = -4 x + 6
y = - x+2
and the y-intercept is ( 0, 2 ) . As with the prev...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12