Alg_Complete

# Here is the simplification for this rational

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Unformatted text preview: subtraction so be on the lookout for it. [Return to Problems] (e) 4 1 - +1 y+2 y The point of this problem is that “1” sitting out behind everything. That isn’t really the problem that it appears to be. Let’s first rewrite things a little here. 4 11 -+ y+2 y 1 In this way we see that we really have three fractions here. One of them simply has a denominator of one. The least common denominator for this part is, lcd : y ( y + 2 ) Here is the addition and subtraction for this problem. y ( y + 2) y+2 4 11 4y -+= + y + 2 y 1 ( y + 2 )( y ) y ( y + 2 ) y ( y + 2 ) = 4 y - ( y + 2) + y ( y + 2) y ( y + 2) Notice the set of parenthesis we added onto the second numerator as we did the subtraction. We are subtracting off the whole numerator and so we need the parenthesis there to make sure we don’t make any mistakes with the subtraction. Here is the simplification for this rational expression. 4 1 1 4 y - y - 2 + y2 + 2 y y2 + 5 y - 2 -+= = y+2 y 1 y ( y + 2) y ( y + 2) [Return to Problems] © 2007 Paul Dawkins 51 http://tutorial.math.lamar.edu/terms.aspx College Algebra Complex Numbers The last topic i...
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## This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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