Alg_Complete

# However recall that whenever we divide both sides of

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Unformatted text preview: id catch the fact that the direction of the inequality changed here didn’t you? We divided by a “-7” and so we had to change the direction. The inequality form of the solution is m > 13 . 7 æ 13 ö ,¥÷ . è7 ø The interval notation for this solution is, ç [Return to Problems] (b) 2 (1 - x ) + 5 £ 3 ( 2 x - 1) Again, not much to do here. 2 (1 - x ) + 5 £ 3 ( 2 x - 1) 2 - 2x + 5 £ 6x - 3 10 £ 8 x 10 £x 8 5 £x 4 Now, with this inequality we ended up with the variable on the right side when it more traditionally on the left side. So, let’s switch things around to get the variable onto the left side. Note however, that we’re going to need also switch the direction of the inequality to make sure that we don’t change the answer. So, here is the inequality notation for the inequality. x³ é5 5 4 ö The interval notation for the solution is ê , ¥ ÷ . ë4 ø [Return to Problems] Now, let’s solve some double inequalities. The process here is similar in some ways to solving sin...
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