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Unformatted text preview: the center are zero. By comparing our equation with the standard form it’s fairly easy to see (hopefully…) that the x coordinate of the center is 1. The y coordinate isn’t too bad either, but we do need to be a little careful. In this case the term is ( y + 4) 2 and in the standard form the term is ( y - k ) . Note that the signs are different. The 2 only way that this can happen is if k is negative. So, the y coordinate of the center must be -4. © 2007 Paul Dawkins 171 http://tutorial.math.lamar.edu/terms.aspx College Algebra The center and radius for this circle are, center = (1, -4 ) radius = 16 = 4 Here is a sketch of this circle with the center marked with a red cross. [Return to Problems] So, we’ve seen how to deal with circles that are already in the standard form. However, not all circles will start out in the standard form. So, let’s take a look at how to put a circle in the standard form. Example 3 Determine the center and radius of each of the following. (a) x 2 + y 2 + 8 x + 7 = 0 [Solution] (b) x 2 + y 2 - 3 x +...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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