However this isnt the nonsense that the first part

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Unformatted text preview: apparent soon enough. é 1 -1 -3 -16 ù é 1 -1 -3 -16 ù ê0 4 7 ú R2 « R3 ê0 -2 0 -10 ú 41ú ê ú ®ê ê0 -2 0 -10 ú ê0 4 7 41ú ë û ë û Now, if we divide the second row by -2 we get the 1 in that spot that we want. é 1 -1 -3 -16 ù 1 é 1 -1 -3 -16 ù ê0 -2 0 -10 ú - R2 ê0 1 0 5ú ê ú2 ê ú ê0 4 7 41ú ® ê0 4 7 41ú ë û ë û Before moving onto the next step let’s think notice a couple of things here. First, we managed to avoid fractions, which is always a good thing, and second this row is now done. We would have eventually needed a zero in that third spot and we’ve got it there for free. Not only that, but it won’t change in any of the later operations. This doesn’t always happen, but if it does that will make our life easier. Now, let’s use the third row operation to change the red 4 into a zero. © 2007 Paul Dawkins 333 http://tutorial.math.lamar.edu/terms.aspx College Algebra é 1 -1 -3 -16 ù é 1 -1 -3 -16ù ê0 1 0 ú R3 - 4 R2 ® R3 ê0 1 0 5ú 5ú ê...
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