Unformatted text preview: ow we can find
the new slope as follows, m2 = - 1
10 Then, just as we did in the previous part we can use the point-slope form of the line to get the
equation of the new line. Here it is, 10
( x - 8)
= 2+ x3
y = x3
y = 2+ © 2007 Paul Dawkins 168 [Return to Problems] http://tutorial.math.lamar.edu/terms.aspx College Algebra Circles
In this section we are going to take a quick look at circles. However, before we do that we need
to give a quick formula that hopefully you’ll recall seeing at some point in the past.
Given two points ( x1 , y1 ) and ( x2 , y2 ) the distance between them is given by, ( x2 - x1 ) + ( y2 - y1 )
2 d= 2 So, why did we remind you of this formula? Well, let’s recall just what a circle is. A circle is all
the points that are the same distance, r – called the radius, from a point, ( h, k ) - called the center.
In other words, if ( x, y ) is any point that is on the circle then it has a distance of r from the
center, ( h, k ) .
If we use the distance formula on these two points we would get, r= ( x - h) + ( y - k )
2 2 Or, if we square both sides we get, ( x - h) + ( y...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12