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Unformatted text preview: - 2) = 0 From the first factor we get that x = 0 and from the second we get that x = 2 . These are the two 5 solutions to this equation. Note that is we’d canceled an x in the first step we would NOT have gotten x = 0 as an answer! [Return to Problems] Let’s work another type of problem here. We saw some of these back in the Solving Linear Equations section and since they can also occur with quadratic equations we should go ahead and work on to make sure that we can do them here as well. Example 2 Solve each of the following equations. 1 5 (a) = 1[Solution] x +1 2x - 4 3 4- x (b) x + 3 + = [Solution] x -1 x -1 Solution Okay, just like with the linear equations the first thing that we’re going to need to do here is to clear the denominators out by multiplying by the LCD. Recall that we will also need to note value(s) of x that will give division by zero so that we can make sure that these aren’t included in the solution. © 2007 Paul Dawkins 88 College Algebra...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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