Unformatted text preview: his can’t be
broken up any farther. Also, we can only deal with exponents if the term as a whole is raised to
the exponent. The fact that both pieces of this term are squared doesn’t matter. It needs to be the
whole term squared, as in the first logarithm.
So, we can further simplify the first logarithm, but the second logarithm can’t be simplified any
more. Here is the final answer for this problem. æ ( x + y )2 ö
log 3 ç 2
÷ = 2 log 3 ( x + y ) - log3 ( x 2 + y 2 )
ç x + y2 ÷
[Return to Problems] © 2007 Paul Dawkins 292 http://tutorial.math.lamar.edu/terms.aspx College Algebra Now, we need to work some examples that go the other way. This next set of examples is
probably more important than the previous set. We will be doing this kind of logarithm work in a
couple of sections. Example 5 Write each of the following as a single logarithm with a coefficient of 1.
(a) 7 log12 x + 2 log12 y [Solution]
(b) 3 log x - 6log y [Solution]
(c) 5ln ( x + y ) - 2 ln y - 8ln x [Solution] Solution
The instruction requiring a coefficient of 1 means t...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12